105=(3x^2+21x+30)/2

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Solution for 105=(3x^2+21x+30)/2 equation: 



105=(3x^2+21x+30)/2

We move all terms to the left:

105-((3x^2+21x+30)/2)=0

We multiply all the terms by the denominator


-((3x^2+21x+30)+105*2)=0



We calculate terms in parentheses: -((3x^2+21x+30)+105*2), so:

(3x^2+21x+30)+105*2

We add all the numbers together, and all the variables

(3x^2+21x+30)+210

We get rid of parentheses

3x^2+21x+30+210

We add all the numbers together, and all the variables

3x^2+21x+240

Back to the equation:

-(3x^2+21x+240)



We get rid of parentheses

-3x^2-21x-240=0

a = -3; b = -21; c = -240;
Δ = b2-4ac
Δ = -212-4·(-3)·(-240)
Δ = -2439
Delta is less than zero, so there is no solution for the equation

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